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Huawei H12-831_V1.0 (HCIP-Datacom-Advanced Routing & Switching Technology V1.0) Certification Exam is a comprehensive test that evaluates the knowledge and skills of IT professionals in advanced routing and switching technologies. HCIP-Datacom-Advanced Routing & Switching Technology V1.0 certification is designed to equip professionals with the necessary skills to design, deploy, and maintain complex networks using Huawei routing and switching products. H12-831_V1.0-ENU exam covers a wide range of topics, including network design principles, routing protocols, network security, and advanced switching technologies.

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Huawei HCIP-Datacom-Advanced Routing & Switching Technology V1.0 Sample Questions (Q52-Q57):

NEW QUESTION # 52
[According to this picture, Peimen can judge?
cR3>display ipv6 routing-table protocol isis

A. R3The device type must beLevel-2
B. unable to judgeR3type of device
C. R3The device type must beLevel-1-2
D. R3The device type must beLevel-1

Answer: C

NEW QUESTION # 53
IS-IS is a link-state routing protocol that uses the SPF algorithm for route calculation. As shown in the figure, a campus deploys both IPv4 and IPv6 and runs IS-IS to achieve network interconnection. R2 only supports IPv4. Which of the following statements is true about the topology calculation of this network?

A. If you want IPv4 and IPv6 network computation to form the same shortest path tree, you need to run the ipv6 enable topology ipv6 command to enable the IPv6 capability in the IS-IS process.
B. By default, IPv4 and IPv6 networks will be calculated separately to form different shortest path trees
C. By default, since R2 does not support IPv6, in the shortest path tree formed by IPv6 network calculation, the path from R1 to R4 is: R1-R3-R4
D. By default, in the shortest path tree formed by IPv6 network calculation, the path from R1 to R4 is: R1-R2-R4. Since R2 does not support IPv6, R2 will directly discard IPv6 packets after receiving them, causing traffic loss.

Answer: C

NEW QUESTION # 54
On the network shown in the figure, a network engineer finds that the path between PC1 and PC2 is not the optimal path, and all links along the path have the same cost.
Given this, which of the following routers may be the root bridges of the Layer 2 network?

Options:

A. SW1
B. SW3
C. SW4
D. SW2

Answer: A,C

Explanation:
Comprehensive and Detailed In-Depth Explanation:
Understanding the Spanning Tree Protocol (STP) and Root Bridge Selection
* Spanning Tree Protocol (STP) is used to prevent loops in a Layer 2 network by electing a Root Bridge and determining a loop-free topology.
* The Root Bridge is elected based on the lowest Bridge ID (BID), which consists of:
* Priority Value (Lower is preferred, default is 32768).
* MAC Address (Lower MAC wins in case of a tie).
* The optimal forwarding path is chosen based on cost, which is usually determined by the link bandwidth.
Why the Path is Not Optimal?
* The network engineer states that all links have the same cost, meaning that the STP Root Bridge election determines the topology rather than cost differences.
* The fact that the path between PC1 and PC2 is suboptimal suggests that the Root Bridge may not be ideally placed.
Determining the Likely Root Bridge:
* The Root Bridge is the switch with the lowest BID (priority + MAC).
* All switches calculate the shortest path to the Root Bridge and place ports in either Forwarding or Blocking mode.
* From the diagram, the traffic is flowing through SW2 # SW4 # SW3 instead of directly via SW2 # SW3.
* This suggests that the Root Bridge is likely SW1 or SW4 because:
* Root Bridges do not block any ports.
* If SW1 or SW4 is the Root Bridge, the spanning tree topology might force the path to take a longer route.
Key Takeaways:
* Root Bridge selection influences the entire Layer 2 forwarding path.
* The lowest Bridge ID (priority + MAC) determines the Root Bridge.
* If a suboptimal path is taken, the Root Bridge is likely placed in a location that forces certain links to block.
* In this scenario, SW1 or SW4 is the most probable Root Bridge, forcing traffic through an unintended path.
HCIP-Datacom-Advanced Routing & Switching Technology References:
* Huawei HCIP-Datacom Official Certification Guide, Chapter on Spanning Tree Protocol (STP) and Root Bridge Selection.
* Huawei Datacom Training Materials, Section on STP Convergence and Network Optimization.
* Huawei Datacom Configuration Guide, Command Reference for STP Root Bridge Selection and Path Calculation.

NEW QUESTION # 55
OSPFv2 is an IGP running on an IPv4 network; OSPFv3 is an IGP running on an IPv6 network. The basic working mechanism of OSPFv3 is the same as OSPFv2, such as the election of DR and BDR. As shown in the figure, an engineer uses three routers to test IPv6 services. He wants to realize the interconnection and interoperability of IPv6 networks by running OSPFv3.

Which of the following statements regarding the election of DR on this network is correct?

A. After the network converges, R1 is powered off and restarted. When the network converges again, R3 is the DR
B. After the network converges, a new device R4 is added to the broadcast link, and the priority of R4 is 150. When the network converges again, R4 is the DR
C. After the network converges, R1 is the DR
D. After the network converges, the engineer changes the priority of R1 to 100, the priority of R2 to 10, and the default value of R3. When the network converges again, R1 is DR and R2 is BDR

Answer: A

NEW QUESTION # 56
The description of the MPLS forwarding mechanism is correct

A. ifTunnel IDvalue is0x0test entryMPLSForwarding process
B. whenIPmessage entryMRLSdomain, the first thing to look at isFIBsurface
C. ifTumel IDvalue is not0x0,into the normalIPForwarding process
D. The system automatically allocates aI. also known asTunnel ID

Answer: B,D

NEW QUESTION # 57
......

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Colin Harris Colin Harris

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